NCERT Solutions for Class 12th: Ch 6 Molecular Basis of Inheritance Biology
Exercises
Page No: 125
1. Group the following as nitrogenous bases and nucleosides:
Adenine, Cytidine, Thymine, Guanosine, Uracil and Cytosine.
Answer
Nucleosides are Cytidine, Guanosine and Cytosine.
Answer
% of C = % of G
Therefore, the percent of guanine = 20The percent of thymine + adenine will be 100 - (20 + 20) = 60
Therefore, the percent of adenine will be 60/2 = 30
5′-ATGCATGCATGCATGCATGCATGC-3′
Write down the sequence of the complementary strand in the 3′ → 5′ direction.
Answer
The sequence of the complementary strand in the 3′→5′ direction will be 3'-TACGTACGTACGTACGTACGTACGTACG-5'.
5'-ATGCATGCATGCATGCATGCATGCATGC-3'
Write down the sequence of m-RNA.
Answer
3'-TACGTACGTACGTACGTACGTACGTACG-5'
Thus, the sequence of mRNA will be
5'-AUGCAUGCAUGCAUGCAUGCAUGCAUGC-3'
Answer
The property of DNA double helix led Watson and Crick are:
• Two strands running opposite to each other, wherein bases will always pair with their counterpart-A with T and G with C (specific pairing).
• If H bonds break and bases of one strand lie exposed, unpaired, they will easily pair up with free nucleotides as well.
This type of arrangement in DNA molecule led to the hypothesis that DNA replication is semi-conservative. where the two strands separate and act as a template for the synthesis of a new complementary strand.
6. Depending upon the chemical nature of the template (DNA or RNA) and the nature of nucleic acids synthesised from it (DNA or RNA), list the types of nucleic acid polymerases.
Answer
• DNA-dependent DNA polymerase uses a DNA template to catalyse the polymerisation deoxynucleotides.
• DNA-dependent RNA polymerase catalyses the transcription of all types of RNA (in bacteria).
• DNA-dependent RNA polymerase-I transcribes rRNA.
• DNA-dependent RNA polymerase-II transcribes the precursor of mRNA (hnRNA).
• DNA-dependent RNA polymerase-III transcribes tRNA.
7. How did Hershey and Chase differentiate between DNA and protein in their experiment while proving that DNA is the genetic material?
Answer
According to Hershey and Chase experiment:
• They grew some bacteriophages on a medium that contained radioactive phosphorus and some in another medium that contained radioactive sulphur.
• Viruses grown in the presence of radioactive phosphorus contained radioactive DNA but not radioactive protein as phosphorus is present only in DNA.• They grew some bacteriophages on a medium that contained radioactive phosphorus and some in another medium that contained radioactive sulphur.
• Viruses grown on radioactive sulphur contained radioactive protein but not radioactive DNA because DNA does not contain sulphur.
• It was found that bacteria which were infected with bacteriophages that had radioactive DNA were radioactive, indicating that DNA was the material that passed from the virus to the bacteria.
• Bacteria that were infected with viruses that had radioactive proteins were not radioactive. This indicated that proteins did not enter the bacteria from the viruses.
• This was a clear proof that DNA is the genetic material that is passed from virus to bacteria.
8. Differentiate between the followings:
(a) Repetitive DNA and Satellite DNA(b) mRNA and tRNA
(c) Template strand and Coding strand
Answer
(a) Repetitive DNA and Satellite DNA
(a) Repetitive DNA and Satellite DNA
Repetitive DNA
|
Satelite DNA
|
It is the non-coding DNA with multiple copies of identical sequences which may lie in tandem or interspersed. | It refers to non-coding tandem repeat sequences. |
These can be few base pairs to hundreds or thousands of base pairs. | These are generally short sequence repeats (up to 60 base pair long). |
It appears as light bands. | It appears as small dark bands. |
(b) mRNA and tRNA
mRNA
|
tRNA
|
It is called messenger RNA and carries the codes for amino acid sequence. | It is called transfer RNA as it carries amino acids to the site of protein synthesis. |
It is a linear molecule. | It has clover leaf shape. |
It is synthesised by RNA polymerase II | It is synthesised by RNA polymerase III. |
(c) Template strand and Coding strand
Template strand
|
Coding strand
|
It is the strand which is transcribed into RNA. | It has the same sequence as mRNA. |
It is called anti sense strand. | It is called sense or non-template strand. |
It has 3'→ 5' polarity. | It has 5'→ 3' polarity. |
9. List two essential roles of ribosome during translation.
Answer
Two essentials roles of ribosomes during translation are:
• The ribosome binds to mRNA and provides a platform for joining of amino acids.
• It also acts as a catalyst (23 SrRNA in bacteria is the enzyme ribozyme) for the formation of a peptide bond.
Answer
Lactose regulates switching on and off of the lac operon.
If lactose is provided in the growth medium of the bacteria, it is transported into the cells through the action of permease.
The repressor of the operon is synthesized all the time from the i gene. It binds the repressor protein which binds to the operator region of the operon and prevents RNA polymerase from transcribing the
operon. In the presence of an inducer, such as lactose or allolactose, the repressor is inactivated by interaction with the inducer. This allows RNA polymerase access to the promoter and transcription proceeds.
11. Explain (in one or two lines) the function of the followings :
(a) Promoter
(b) tRNA
(c) Exons
Answer
(a) Promoter: It is a region of DNA that helps in initiating the process of transcription. It serves as the binding site for RNA polymerase.
(b) tRNA: tRNA or transfer RNA is a small RNA that reads the genetic code present on mRNA. It carries specific amino acid to mRNA on ribosome during translation of proteins.
(c) Exons: Exons are the coding sequences of DNA that are transcribed and translated.
12. Why is the human genome project called a mega project?
Answer
Human genome project is called a mega project because
• Its aim was to determine the nucleotide sequence of complete human genome which was a task of enormous magnitude.
• A total of 3 10 9 × base pairs were to be sequenced and the cost was about 9 billion US dollars.
• It required bioinformatics data base techniques and other contemporary devices for the analysis, storage and retrieval of information.
• Many countries worked jointly to complete this timed project.
13. What is DNA fingerprinting? Mention its application.
Answer
DNA fingerprinting is a technique used to identify and analyze the variations in various individuals at the level of DNA.
Its Application• It is used in forensic science to identify potential crime suspects.
• It is used to settle parental disputes.
• It is used to identify and protect the commercial varieties of crops and livestock.
• It is used to find out the evolutionary history of an organism and trace out the linkages between groups of various organisms.
(a) Transcription
(b) Polymorphism
(c) Translation
(d) Bioinformatics
Answer
(a) Transcription: The process of copying genetic information from one strand of the DNA into RNA is known as transcription. RNA is assembled simply based on complementarity of the DNA strand, only uracil is substituted in place of thymine. Only a small segment of DNA that codes for a polypeptide is copied.
(b) Polymorphism: The variation in DNA arising through mutation at non-coding sequences is known as Polymorphism. Such variations are unique to specific sites of DNA and can occur due to deletion, insertion or substitution of bases. It can be observed by making fragments of DNA sample and separating them through electrophoresis.The polymorphism in a DNA sequence is the basis of genetic mapping of the human genome as well as DNA fingerprinting.
(c) Translation: It refers to the process of polymerisation of amino acids to form a polypeptide. The order and sequence of amino acids are defined by the sequence of bases in the mRNA. It occurs in cytoplasm in both prokaryotes and eukaryotes.
(d) Bioinformatics: It is the application of computer science and information technology which deals with handling, storing of huge information of genomics, processing information, analyzing data and creating new knowledge.