Class 12 Maths NCERT Solutions for Chapter 7 Integrals Exercise 7.1
Integrals Exercise 7.1 Solutions
1. Find an anti derivative (or integral) of the following functions by the method of inspection.
sin 2x .
Solution
The anti derivative of sin 2x is a function of x whose derivative is sin 2x.
It is known that,
Therefore, the anti derivative of sin2x is -1/2 cos 2x
2. Find an anti derivative (or integral) of the following functions by the method of inspection.
cos 3x .
Solution
The anti derivative of cos 3x is a function of x whose derivative is cos 3x.
It is known that,
Therefore, the anti derivative of cos3x is (1/3) sin 3x.
3. Find an anti derivative (or integral) of the following functions by the method of inspection.
e2x.
Solution
The anti derivative of e2x is the function of x whose derivative is e2x.
It is known that,
Therefore, the anti derivative of e2x is (1/2) e2x.
4. Find an anti derivative (or integral) of the following functions by the method of inspection.
(ax + b)2
Solution
The anti derivative of (ax + b)2 is the function of x whose derivative is (ax + b)2 .
It is known that,
Therefore, the anti derivative of (ax + b)2 is (1/3a)(ax + b)3.
5. Find an anti derivative (or integral) of the following functions by the method of inspection
sin 2x – 4 e3x.
Solution
The anti derivative of (sin2x - 4e3x) is the function of x whose derivative is (sin 2x - 4e3x).
It is known that,
Therefore, the anti derivative of (sin2x - 4e3x) is
6. Find the following integrals ∫(4 e3x + 1) dx
Solution
= ∫(sec2 x + sec x tan x)dx
= ∫ sec2 x dx + ∫ sec x tan x dx
= tan x + sec x + c
(B) (2/3)x2/3 + (1/2)x2 + C
(C) (2/3)x3/2 + 2x1/2 + C
(D) (3/2)x3/2 + (1/2)x1/2 + C
Hence, the correct answer is C.
(A) x4 + 1/x3 - 129
(B) x3 + 1/x4 + 129/8
(C) x4 + 1/x3 + 129/8
(D) x3 + 1/x4 - 129/8