Class 11 Maths NCERT Solutions for Chapter 15 Statistics Exercise 15.3
Statistics Exercise 15.3 Solutions
1. From the data given below state which group is more variable, A or B?
Marks |
10-20 |
20-30 |
30-40 |
40-50 |
50-60 |
60-70 |
70-80 |
Group A |
9 |
17 |
32 |
33 |
40 |
10 |
9 |
Group B |
10 |
20 |
30 |
25 |
43 |
15 |
7 |
Marks |
Group A fi |
Mid – point xi |
yi2 |
fi yi |
fi yi2 |
|
10 – 20 |
9 |
15 |
-3 |
9 |
-27 |
81 |
20 – 30 |
17 |
25 |
-2 |
4 |
-34 |
68 |
30 – 40 |
32 |
35 |
-1 |
1 |
-32 |
32 |
40 – 50 |
33 |
45 |
0 |
0 |
0 |
0 |
50 – 60 |
40 |
55 |
1 |
1 |
40 |
40 |
60 – 70 |
10 |
65 |
2 |
4 |
20 |
40 |
70 – 80 |
9 |
75 |
3 |
9 |
27 |
81 |
150 |
-6 |
342 |
The standard deviation of group B is calculated as follows.
Marks |
Group A fi |
Mid – point xi |
yi2 |
fi yi |
fi yi2 |
|
10 – 20 |
10 |
15 |
-3 |
9 |
-30 |
90 |
20 – 30 |
20 |
25 |
-2 |
4 |
-40 |
80 |
30 – 40 |
30 |
35 |
-1 |
1 |
-30 |
30 |
40 – 50 |
25 |
45 |
0 |
0 |
0 |
0 |
50 – 60 |
43 |
55 |
1 |
1 |
43 |
43 |
60 – 70 |
15 |
65 |
2 |
4 |
30 |
60 |
70 – 80 |
7 |
75 |
3 |
9 |
21 |
63 |
150 |
-6 |
366 |
Since the mean of both the groups is same, the group with greater standard deviation will be more variable.
Thus, group B has more variability in the marks.
X |
35 |
54 |
52 |
53 |
56 |
58 |
52 |
50 |
51 |
49 |
Y |
108 |
107 |
105 |
105 |
106 |
107 |
104 |
103 |
104 |
101 |
35, 54, 52, 53, 56, 58, 52, 50, 51, 49
Here, the number of observations, N = 10
The following table is obtained corresponding to shares X.
xi |
||
35 |
-16 |
256 |
54 |
3 |
9 |
52 |
1 |
1 |
53 |
2 |
4 |
56 |
5 |
25 |
58 |
7 |
49 |
52 |
1 |
1 |
50 |
-1 |
1 |
51 |
0 |
0 |
49 |
-2 |
4 |
350 |
The prices of share Y are
108, 107, 105, 105, 106, 107, 104, 103, 104, 101
The following table is obtained corresponding to shares Y.
yi |
|
|
108 |
3 |
9 |
107 |
2 |
4 |
105 |
0 |
0 |
105 |
0 |
0 |
106 |
1 |
1 |
107 |
2 |
4 |
104 |
-1 |
1 |
103 |
-2 |
4 |
104 |
-1 |
1 |
101 |
-4 |
16 |
40 |
C.V. of prices of shares X is greater than the C.V. of prices of shares y.
Firm A |
Firm B |
|
No. of wage earners |
586 |
648 |
Mean of monthly wages |
Rs 5253 |
Rs 5253 |
Variance of the distribution of wages |
100 |
121 |
(ii) Which firm, A or B, shows greater variability in individual wages?
(i) Monthly wages of firm A = Rs 5253
Number of wage earners in firm A = 586
∴Total amount paid = Rs 5253 × 586
Monthly wages of firm B = Rs 5253
Number of wage earners in firm B = 648
∴Total amount paid = Rs 5253 × 648
Thus, firm B pays the larger amount as monthly wages as the number of wage earners in firm B are more than the number of wage earners in firm A.
(ii) Variance of the distribution of wages in firm A (σ12) = 100
∴ Standard deviation of the distribution of wages in firm
A ((σ1) = √100 = 10
Variance of the distribution of wages in firm B (σ22) = 121
∴ Standard deviation of the distribution of wages in firm B (σ22) = √121 = 11
The mean of monthly wages of both the firms is same i.e., 5253. Therefore, the firm with greater
standard deviation will have more variability.
Thus, firm B has greater variability in the individual wages.
4. The following is the record of goals scored by team A in a football session:
No. of goals scored |
0 |
1 |
2 |
3 |
4 |
No. of matches |
1 |
9 |
7 |
5 |
3 |
No. of goals scored |
No. of matches |
fi xi |
xi2 |
fixi2 |
0 |
1 |
0 |
0 |
0 |
1 |
9 |
9 |
1 |
9 |
2 |
7 |
14 |
4 |
28 |
3 |
5 |
15 |
9 |
45 |
4 |
3 |
12 |
16 |
48 |
|
25 |
50 |
|
130 |
The standard deviation of team B is 1.25 goals.
The average number of goals scored by both the teams is same i.e., 2. Therefore, the team with lower standard deviation will be more consistent.
Thus, team A is more consistent than team B.
5. The sum and sum of squares corresponding to length x (in cm) and weight y (in gm) of 50 plant products are given below:
Which is more varying, the length or weight?
Solution
Thus, C.V. of weights is greater than the c.v. of lengths. Therefore, weights vary more than the lengths.